w^2+30w-10800=0

Solution for w^2+30w-10800=0 equation:

w^2+30w-10800=0

a = 1; b = 30; c = -10800;
Δ = b2-4ac
Δ = 302-4·1·(-10800)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{44100}=210$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-210}{2*1}=\frac{-240}{2}
=-120
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+210}{2*1}=\frac{180}{2}
=90
$